Calculus Forum: Limits & L'H么pital's Rule

Need Help with Limits and L'H么pital's Rule

Welcome to the calculus forum! Discuss and find solutions to problems involving limits and the application of L'H么pital's Rule.

User123

I'm stuck on a problem where I need to evaluate lim (x -> 0) [(sin(x))/x]. I think L'H么pital's Rule might help, but I'm not sure how to apply it.


MathGuru007

Hi User123! You鈥檙e on the right track with L'H么pital鈥檚 Rule. Given that (sin(x))/x becomes 0/0 as x approaches 0, you can differentiate the numerator and the denominator separately. In this case, the derivative of sin(x) is cos(x), and the derivative of x is 1. Thus, lim (x -> 0) [cos(x)/1] = 1. 馃槉